318. Semi-infinite solenoid and super conducting disc

Higgs · Messaggio da **Higgs** » 6 set 2023, 11:56

Yes the strength line of B in A is not parallel to the axis. We can say, considering the angle of $\pi/2$ for r=r/2, that $(r/2):(\pi/2)=(r/3):\alpha$ or $\alpha = \pi/3$ . Hence the proiection of $B_A$ on the axis is $B_{Ax}=\mu_0 I n. cos(\pi/3)= \frac{\mu_0 I n}{2}$ Now if it is correct I'll try 2. and 3.

Tarapìa Tapioco · Messaggio da **Tarapìa Tapioco** » 6 set 2023, 12:02

Physicsguy51 · Messaggio da **Physicsguy51** » 6 set 2023, 12:19

Tarapìa Tapioco ha scritto: ↑6 set 2023, 12:02 Is F = $\frac{1}{2} \mu_0 I I_{ring} A$ , where $A$ is the cross-sectioned area?

Incorrect.

Physicsguy51 · Messaggio da **Physicsguy51** » 6 set 2023, 12:19

Higgs ha scritto: ↑6 set 2023, 11:56 Yes the strength line of B in A is not parallel to the axis. We can say, considering the angle of $\pi/2$ for r=r/2, that $(r/2):(\pi/2)=(r/3):\alpha$ or $\alpha = \pi/3$ . Hence the proiection of $B_A$ on the axis is $B_{Ax}=\mu_0 I n. cos(\pi/3)= \frac{\mu_0 I n}{2}$ Now if it is correct I'll try 2. and 3.

Bravo! Try parts 2 and 3 now.

Tarapìa Tapioco · Messaggio da **Tarapìa Tapioco** » 6 set 2023, 12:27

I've modified my result. Tell me if it's correct, otherwise I will try another way.

Physicsguy51 · Messaggio da **Physicsguy51** » 6 set 2023, 12:44

Tarapìa Tapioco ha scritto: ↑6 set 2023, 12:27 I've modified my result. Tell me if it's correct, otherwise I will try another way.

Incorrect

Tarapìa Tapioco · Messaggio da **Tarapìa Tapioco** » 6 set 2023, 13:05

After many attempts, I calculated it as $F = \frac{\mu_0 I I_{ring} l}{2 \pi d}$ , where $l = 2 \pi r$ and $d = (R-r)$ . If it's correct, I'll write the unfolding, otherwise I'll think about it some more.

Physicsguy51 · Messaggio da **Physicsguy51** » 6 set 2023, 13:29

Tarapìa Tapioco ha scritto: ↑6 set 2023, 13:05 After many attempts, I calculated it as $F = \frac{\mu_0 I I_{ring} l}{2 \pi d}$ , where $l = 2 \pi r$ and $d = (R-r)$ . If it's correct, I'll write the unfolding, otherwise I'll think about it some more.

Incorrect, there's going to be an $L$ in the answer too.

Tarapìa Tapioco · Messaggio da **Tarapìa Tapioco** » 6 set 2023, 13:33

The $L$ would be in $I_{ring}$ , isn't it?

Physicsguy51 · Messaggio da **Physicsguy51** » 6 set 2023, 13:54

Tarapìa Tapioco ha scritto: ↑6 set 2023, 13:33 The $L$ would be in $I_{ring}$ , isn't it?

yeah I think, in final answer there will be a term of L

318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc

Re: 318. Semi-infinite solenoid and super conducting disc